DHARMSOIL MOISTURE–PERMEABILITY AND CAPILLARITY 155
We know,k =qrr
zzlog ( / )e
()21
22
1
π−^2=2 303 2 70 15 100
60 31 3 2910
22.log(/)
(. )××
×−πcm/s= 1.18 × 10–1 mm/s.Example 5.13. Determine the order of magnitude of the composite shape factor in the Poiseulle’s
equation adapted for flow of water through uniform sands that have spherical grains and a
void ratio of 0.9, basing this determination on Hazen’s approximate expression for permeabil-
ity.
Poiseulle’s equation adapted for the flow of water through soil is:k = D e
e
s^2 C3
1..
()γ.
μ+
with the usual notation, C being the composite shape factor.
By Allen Hazen’s relationship,
k = 100 D 102
D 10 is the same as the diameter of grains, Ds, for uniform sands.
∴ k = 100 Ds^2. Here Ds is in cm while k is in cm/s.
Substituting –100 Ds^2 = De
e
s^2 C3
1..
().γ
μ+C =^1001
.. 3μ ()
γ+e
e; here μ is in N-Sec/cm^2 and γ is in N/cm^3.C =100 10 10 1 9
981 10 0976
33×××
××−.
.(.)
since μ = 10–3 N-sec/cm^2 (at 20°C) and γ = 9.81 kN/m^3
= 0.002657.Example 5.14. A cohesionless soil has a permeability of 0.036 cm per second at a void ratio of
0.36. Make predictions of the permeability of this soil when at a void ratio of 0.45 according to
the two functions of void ratio that are proposed.
k 1 : k 2 =e
ee
e13123| () (^112) |
|---|
| ++() |
| 0.036 : k 2 = (. ) |
| . |
| : |
| (. ) |
| . |
| 036 |
| 136 |
| 045 |
| 145 |
| 33 |
| = 0.546 : 1 |
| ∴ k 2 = |
| 1 |
| 0546. |
| × 0.36 mm/s = 6.60 × 10–1 mm/s |
| Also, k 1 : k 2 = e 12 : e 22 |
| 0.036 : k 2 = (0.36)^2 : (0.45)^2 |
| = 0.1296 : 0.2025 |