Geotechnical Engineering

(Jeff_L) #1
DHARM

SHEARING STRENGTH OF SOILS 299

Similarly the other normal stresses and shear stresses are obtained by dividing by the
area of the box and are as follows in kN/m^2 :
Normal stress, σ 80 160 240
Peak shear stress, τmax 80 160 240
Ultimate shear stress, τf 46.4 92.8 139.2
Since more than one set of values are available, graphical method is better:
240

180

120

60

0
60 120 180 240
Normal stress, kN/m^2

Shear stress, kN/m

(^2) Peak
Ultimate
f
f
peak
ultimate
(dense state) : 45°
(loose state) : 30°
by measurement with a protractor
Fig. 8.46 Failure envelopes (Ex. 8.2)
Example 8.3: Calculate the potential shear strength on a horizontal plane at a depth of 3 m
below the surface in a formation of cohesionless soil when the water table is at a depth of 3.5
m. The degree of saturation may be taken as 0.5 on the average. Void ratio = 0.50; grain
specific gravity = 2.70; angle of internal friction = 30°. What will be the modified value of shear
strength if the water table reaches the ground surface? (S.V.U—B.E., (R.R.)—Feb, 1976)
Effective unit weight γ′ =
()
()
G
e



  • 1
    1


. γw



(. )
(.)

270 1
105


+

× 10 = 11.33 kN/m^3

Unit weight, γ, at 50% saturation

= (.)
()

GSe
e

+
1 +

. γw =


(.. .)
(.)

270 05 05
105


+

× 10 = 19.667 kN/m^3

(a) When the water table is at 3.5 m below the surface:
Normal stress at 3 m depth, σ = 19.67 × 3 = 59 kN/m^2
Shear strength, s = σ tan φ for a sand
= 59 tan 30° = 34 kN/m^2 (nearly).
(b) When water table reaches the ground surface:
Effective Normal stress at 3 m depth
σ = γ′. h = 11.33 × 3 = 34 kN/m^2
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