DHARM418 GEOTECHNICAL ENGINEERING
18 m9m54 m27 m30 mHard rockClayG.W.T. 3m
6m1.5 mSandgsat= 18 kN/m ; N = 18^3m = 0.00015 m /kNv^2m = 0.00009vm = 0.000075vm = 0.000045vm = 0.00011v ClayE = 16.2 MN/m
E = 63 MN/m2
2
swelling(a) Plan of foundation (b) Soil profile at the site
Fig. 11.17 Raft foundation (Ex. 11.9)
The foundation is split into four rectangles as shown and Fadum’s’ chart is used:Depth (m) B/z L/z Iσ 4Iσ ∆σz (kN/m^2 )3 3 9 0.247 0.988 320
9 1 3 0.203 0.812 263
15 0.60 1.80 0.152 0.608 197
21 0.43 1.30 0.113 0.452 146
27 0.33 1.00 0.086 0.344 112
33 0.27 0.82 0.067 0.268 87Immediate settlement (Sand):
N = 18 σ 0 = 4.5 × 18 – 1.5 × 9.81 = 66.3 kN/m^2Cs = 1.5Cr
σ 0
But Cr = 400 N = 400 × 18 = 7200 kN/m^2Cs =1 5 7200
66 3.
.×
= 162.9S 1 =H
Cs e.logσσ
σ0
0F +
HGI
KJ∆=(.)
.log.
.615
162 966 3 320
66 3−+F
HGI
e KJ m = 0.0487 m = 48.7 mm
Since most part of the sand below the foundation is submerged customarily it is as-
sumed that the settlement will be doubled.