Geotechnical Engineering

(Jeff_L) #1
DHARM

418 GEOTECHNICAL ENGINEERING


18 m

9m

54 m

27 m

30 m

Hard rock

Clay

G.W.T. 3m
6m

1.5 m

Sandgsat= 18 kN/m ; N = 18^3

m = 0.00015 m /kNv^2

m = 0.00009v

m = 0.000075v

m = 0.000045v

m = 0.00011v Clay

E = 16.2 MN/m
E = 63 MN/m

2
2
swelling

(a) Plan of foundation (b) Soil profile at the site
Fig. 11.17 Raft foundation (Ex. 11.9)
The foundation is split into four rectangles as shown and Fadum’s’ chart is used:

Depth (m) B/z L/z Iσ 4Iσ ∆σz (kN/m^2 )

3 3 9 0.247 0.988 320
9 1 3 0.203 0.812 263
15 0.60 1.80 0.152 0.608 197
21 0.43 1.30 0.113 0.452 146
27 0.33 1.00 0.086 0.344 112
33 0.27 0.82 0.067 0.268 87

Immediate settlement (Sand):
N = 18 σ 0 = 4.5 × 18 – 1.5 × 9.81 = 66.3 kN/m^2

Cs = 1.5

Cr
σ 0
But Cr = 400 N = 400 × 18 = 7200 kN/m^2

Cs =

1 5 7200
66 3

.
.

×
= 162.9

S 1 =

H
Cs e

.log

σσ
σ

0
0

F +
HG

I
KJ


=

(.)
.

log.
.

615
162 9

66 3 320
66 3

−+F
HG

I
e KJ m = 0.0487 m = 48.7 mm
Since most part of the sand below the foundation is submerged customarily it is as-
sumed that the settlement will be doubled.

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