DHARM26 GEOTECHNICAL ENGINEERING
Water content, w =() (. .)
.WW
Wd
d−
×=−
100 25 21×
21100%=040
210100%.
.× = 19.05%Bulk unit weight, γ = W/V = 2.50/150 = 0.0167 N/cm^3
= 16.38 kN/m^3Dry unit weight, γd = γ
().
1 (. )16 38
+ 1 0 1905=
w +kN/m^3= 13.76 kN/m^3Also, γd d N/cm^33 kN/mW
VL == = =
NMO
QP2 10 150 0 014 13 734./..But γd =G
e. w
()
γ
1 +13.76 =26 981
1..
()×
+e(1 + e) = 26 981
13 76..
.× = 1.854e = 0.854Degree of saturation, S = wG
e=0 1905 2 6×
0 854..
.= 0.58= 58%
Aliter. From the phase-diagram (Fig. 2.6)
V = 150 cc
W = 2.50 N
Wd = Ws = 2.10 NWaterSolidsV = 150 cm^3V = 69.23 cmv^3W = 0.40 NwAirVw= 40 cm^3V = 80.77 cms^3 W = 2.10 NsW = 2.50 NFig. 2.6 Phase diagram (Example 2.9)
Ww = (2.50 – 2.10) N
= 0.40 NVw =Ww
γw=040
001.
.= 40 cm^3 ,