DHARM458 GEOTECHNICAL ENGINEERINGThis is twice the angle made by the plane on which the stress conditions are represented
by the point D on the Mohr’s circle. Hence, the angle made by the failure plane with the
horizontal is given by^12 (90°+ φ) or (45° + φ/2). Similarly, from the geometry of the Mohr’scircle for the passive condition,
sin φ =EC
OChv
hv2
213
1313
132
2= −
+= −
+= −
+()/
()/σσ
σσσσ
σσσσ
σσ,since σh is the major principal stress and σv is the minor principal stress for the passive case.
This leads to
σ
σφ
φv
h=−
+1
1sin
sinor σ
σφ
φh
v= +
−1
1sin
sin
σ
σh
vis the coefficient of lateral earth pressure and is denoted by Kp for the passive case.∴ Kp =1
145
2+ 2
−=°+F
HGI
KJsin
sinφ tan
φφ
...(Eq. 13.9)The angle made by the failure plane with the vertical is (45° + φ/2), i.e., with the plane of
which the major principal stress acts.
Thus, the angle made by the failure plane with the horizontal is (45° – φ/2) for the
passive case.
The effective angle of friction, φ′, is to be used for φ, if the analysis is based on effective
stresses, as in the case of submerged or partially submerged backfills. These two states are the
limiting states of plastic equilibrium; all the intermediate states are those of elastic equilib-
rium, which include ‘at rest’ condition.
13.6.2Active Earth Pressure of Cohesionless Soil
Let us consider a retaining wall a vertical back, retaining a mass of cohesionless soil, the
surface of which is level with the top of the wall, as shown in Fig. 13.7 (a).KzogzH Cohesionless soil(unit weight : )g PaKHogH/3(a) Retaining wall with cohesionless
backfill (moving away from the fill)(b) Active pressure
distribution with depth
Fig. 13.7 Active earth pressure of cohesionless soil—Rankine’s theory