DHARMLATERAL EARTH PRESSURE AND STABILITY OF RETAINING WALLS 525
Since wall friction is to be accounted for, Coulomb’s theory is to be applied.
γ = 18 kN/m^3 and H = 12 mKa =sin ( )sin .sin( ) sin( ).sin( )
sin( ).sin( )222
1αφααδ φδ φβ
αδ αβ+−+ +−
−+L
N
M
MO
Q
P
P
α = 90° and β = 0° in this case. φ = 30° and δ = 20°∴ Ka =coscos sin( ).sin
cos2
2
1φδ φδ φ
δ+ +L
N
M
MO
Q
P
P=coscos sin .sin
cos2
23020 1^5030
20°°+ °°
°L
N
M
MO
Q
P
P= 0.132Kp =sin ( )sin .sin( ) sin( ).sin( )
sin( ).sin( )222
1αφααδ φδ φβ
αδ αβ−+− ++
++L
N
M
MO
Q
P
P
Putting α = 90° and β = 0°,Kp =coscossin( ).sin
cos222
1φδφδ φ
δ−L +
N
M
MO
Q
P
P=coscos sin .sin
cos2
23020 1^5030
20°°− °°
°L
N
M
MO
Q
P
P= 2.713Pa =1
21
2γHK^22 ..a=× × ×18 12 (^0132) = 171 kN/m
Pp =
1
2
1
2
γHK^22 ..p=× × ×18 12 2 713 = 3.516 kN/m.
Both Pa and Pp act at a height of (1/3)H or 4 m above the base of the wall and are
inclined at 20° above and below the horizontal, respectively.
Example 13.16: A retaining wall is battered away from the fill from bottom to top at an angle
of 15° with the vertical. Height of the wall is 6 m. The fill slopes upwards at an angle 15° away
from the rest of the wall. The friction angle is 30° and wall friction angle is 15°. Using Cou-
lomb’s wedge theory, determined the total active and passive thrusts on the wall, per lineal
metre assuming γ = 20 kN/m^3.
H = 6 m
β = 15°
α = 75° from Fig. 13.61