DHARMLATERAL EARTH PRESSURE AND STABILITY OF RETAINING WALLS 535Eccentricity, e = (1.317 + 0.565 – 1.750) = 0.132 m
Since this is less than (1/6) b or (1/6) × 3.5 m, no tension occurs at the base.Vertical pressure intensity at the base, σ =W
be
b1 6 345
351 6 0132
35F ±
HGI
KJ=±F ×
HGI
. KJ
.
.
or σmax = 120.88 kN/m^2 at the toeand σmin = 76.26 kN/m, at the heel.
Example 13.27: A trapezoidal masonry retaining wall 1 m wide at top and 3 m wide at its
bottom is 4 m high. The vertical face is retaining soil (φ = 30°) at a surcharge angle of 20° with
the horizontal. Determine the maximum and minimum intensities of pressure at the base of
the retaining wall. Unit weights of soil and masonary are 20 kN/m^3 and 24 kN/m^3 respectively.
Assuming the coefficient of friction at the base of the wall as 0.45, determine the factor of
safety against sliding. Also determine the factor of safety against overturning.
(S.V.U.—B.E., (Part-time)—Dec.,1981)Pai
Pah1.33 mb= 20°1mg= 24 kN/m^3g
f= 20 kN/m
= 30°3Toe x Heel
3mW/R 2 W 1Fig. 13.72 Retaining wall (Ex. 13.27)
For backfill,
γ = 20 kN/m^3 φ = 30° β = 20°Kai = cos β.(cos cos cos )
(cos cos cos )ββφ
ββφ−−
+−22
22= cos.(cos cos cos )
(cos cos cos )2020 20 30
20 20 3022
22°°− °− °
°+ °− °
= 0.414Pai =1
21
2γHK^22 ..ai=× × ×20 4 0 414 66 24=.kN / m