DHARM
586 GEOTECHNICAL ENGINEERING
and settlement as given by Terzaghi and Peck, by Peck, Hanson and Thornburn, and by
Teng.
Details are given in the Appendices of IS: 1904–1986 (Revised), already cited.
14 .16 Illustrative Examples
Example 14.1: Calculate the elastic settlement of a rectangular foundation, 6 m × 12 m, on a
uniform sand with E = 20,000 kN/m^2 and Poisson’s ratio, ν = 0.2. The contact pressure is 200
kN/m^2. The settlements are to be calculated at the centre, mid-point of long side, and mid-
point of short side, and at the free corner.
Also compute the allowable bearing pressure, if the maximum settlement is restricted
to 40 mm.
Side ratio of rectangle = 12/6 = 2
The elastic settlement is given by Schleicher as s = K.q. A
E
.()10
−^2
K = shape factor = 1.08, 0.79, 0.69, and 0.54 for the centre, mid-point of long side, mid-
point of short-side, and free corner respectively. (Table 14.2)
∴ Settlement at the centre
= 1.08 × 200 × 12 6
102
20 000
2
×
(.)−
,
× 1000 mm = 88 mm.
Settlement at the mid-point of long-side
= 0.79 × 200 × 72 102
20 000
(.)^2
,
− × 1000 mm = 64.4 mm
Settlement at the mid-point of short-side
= 0.69 × 200 × 72 102
20 000
(.)^2
,
− × 1000 mm = 56.2 mm
Settlement at the free corner
= 0.54 × 200 × 72
102
20 000
(.)^2
,
−
× 1000 mm = 44 mm
If the maximum settlement is restricted to 40 mm, the centre settlement should not
exceed this value.
Then the allowable bearing pressure:
q = sE
A()1−ν^2
=
40 20 000
108 72 1 02^2
×
×−
,
.(.)
≈ 90 kN/m^2.
Example 14.2: What is the minimum depth required for a foundation to transmit a pressure
60 kN/m^2 in a cohesionless soil with γ = 18 kN/m^3 and φ = 18°? What will be the bearing
capacity if a depth of 1.5 m is adopted according to Rankine’s approach?
γ = 18 kN/m^3 φ = 18° q = 60 kN/m^2.
Minimum depth of foundation, according to Rankine,
Df =
q
γ
φ
φ
1
1
2
−
+
F
HG
I
KJ
sin
sin
=
60
18
118
118
2
−°
+°
F
HG
I
KJ
sin
sin
= 0.93 m ≈ 1 m