Geotechnical Engineering

(Jeff_L) #1
DHARM

774 GEOTECHNICAL ENGINEERING


Ht. of centre of buoyancy, B, above the base

AB=

545
2

.
= 2.725 m

AG is given as 4.200 m
∴ BG = 4.200 – 2.725 = 1.475 m

BM(M being the Metacentre) =

I
V
=

1
12

18 9^1
882 35

×××^3
.

= 1.240 m

∴ AM=+AB BM = 2.725 + 1.240 = 3.965 m

AG being 4.200 m, M is below G, and the metacentric height MG is negative (the nu-
merical value of MG is 0.235 m). The caisson is, therefore, unstable.


The caisson can be made stable by filling it with, say, sand ballast (Assume γsand = 22
kN/m^3 ).


Let us try a thickness of 0.5 m of sand.
The height of the new centre of gravity, G′, above the base

AG′ =

9000 4 2 9 18 0 5 22 0 25
9000 9 18 0 5 22

×+××××
+× × ×

...
(.)

m

= 3.55 m

9m

10 m
G

A

4.2 m

Fig. 19.9 Stability of box caisson (Ex. 19.3)

New depth of immersion, d′ =

()
.

9000 1782
10 2 9 18

+
×× = 6.525 m

(^) AB′=6 525
2


. m = 3.263 m


BM I V′′= = × × ×
××

/(/)
.

112 18 9

1
9 18 6 525

(^3) m = 1.035 m
AM′=AB′+ ′ ′B M = 3.263 + 1.035 = 4.298 m
Since AM′>AG′, M′ is above G′( ...MG′′=4 298 3 550 0 748 m)− =. Since M′ is above G′,
the metacentric height M′G′ being positive, the caisson is stable.

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