Geotechnical Engineering

(Jeff_L) #1
DHARM

CAISSONS AND WELL FOUNDATIONS 797


From equations 19.40 and 19.43,

P =

()
()

HWmKI.
D

+ vv
+′

βμ =
βμμ

θ
1

2

Using Eq. 19.46,

P =

2 mI
D

v(/) /MI Mr= ...(Eq. 19.48)

where r = (/)D.


I
mIv

2

Also H + βμW =

M
r

()1+′βμμ

Simplifying,

H + βμW =

M
r

M
r

+

βμμ′

or βμW μμ


M
r

FHG − ′I
KJ

= M
r

−H

or β =


(/)

()

Mr H

W M
r


L −′
NM

O
QP

μμμ

...(Eq. 19.49)

As – 1 < β < 1, we have
M
r

WHM
r

F ()+′− ()11W
HG

I
KJ

<<F −′+
HG

I
KJ

μμ μ μμ μ

The vertical soil reaction is given by
σz = Kvθ(x + xc)

Also W – μ′P = σθzv cdA=+K zz ()x x dA


or W – μ′P = KvθxcA


or Kvθxc =


()WP
A

−′μ

∴σz = Kx

WP
v A
θ +()−′μ ...(Eq. 19.50)

The stresses at the toe and the heel are given by

pt =

()WP
A

−′ +KvFB
HG

I
KJ

μ θ
2

...(Eq. 19.51 (a))

ph =

()WP
A

−′ −Kv FB
HG

I
KJ

μ θ
2

...(Eq. 19.51 (b))

Substituting the value of Kvθ from Eq. 19.45,

pt =

()WP
A

MB
I

−′μ +
2

...(Eq. 19.52 (a))

ph =

()WP
A

MB
I

−′

μ
2

...(Eq. 19.52 (b))
For the soil to remain in the elastic state, the maximum pressure at any depth should
not exceed the passive resistance.

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