Engineering Economic Analysis

(Chris Devlin) #1
.
Applying Present Wort~ Techniques 161

\:~1{~ ~~~~


Two pieces of construction equipment are being analyzed:


Year


o 1 2 3 4 5 6 7 8

Alt.A
-$2000
+ 1000
+850
+700
+550
+400
+400
+400
+400

Alt.B
-$1500
+700
+300
+300
+300
+300
+400
+500
+600
Based on an 8% interest rate, which alternative should be selected?

.. "..SOUUTION'J'".'. -. I',,,-.. _ ~Joo;
AlternativeA
l00


r


~--850- - --- __ 700 -r- --- J

---1--==f===~--4r---i9---iF--~
0-1-2-3-4-5-6-7-8

1
2000

PW of benefits =400(PlA,8%, 8) +600(PI A,8%,4) - 150(PIG,8%,4)


= 400(5.747) + 600(3.312) - 150(4.650) -' 3588.50


PW of cost= 2000


Net present worth=3588.50- 2000 =+$1588.50


AlternativeB

I
I


I
r


L


.1

= = Ii::



,
I

1500

.~
I
I

I

:::: ..... ~-
Free download pdf