I
Analysis Period 189
of each alternative throughout the analysis period and, in addition, see what differences
there might be in salvage values, and so forth, at the end of the analysis period.
Suppose that Alternative 1 has a 7-year life and a salvage value at the end of that time. The
replacement cost at the end of 7 years may be more or less than the original cost. If the replacement
is retired prior to 7 years, it will have a terminal value that exceeds the end-of-life salvage value.
Alternative 2 has a 13-year life and a terminal value wheneverit isretired. If the situation indicates
that 10 years is the proper analysis period, set up the equations to properly compute the EUAC
for each alternative.
Alternative 1
Salvage TerminalValueat
Value End of 10th Year
f f
O~1-2~3---:::-4~5~6~1---8---9-1O-11---12-13---14
l
,jnitii1 R"Plae<meni
l
.. i
Cost Cost II
I 7~yearLife I 7-yearLifeI
Altemative2 Terminal Value at
End of 1OthYear
f
O~1-2-3___4~5 6" 7~8 9~10 11---12-13
l
1'titii1
Cost
,'
13-year Life I
I
--I
II
10-year Analysis Period
Altel'native.l
'.
EUAC1 [Initial cost + (Replacetnent cost- Salvage value)(Pj F, i, 7,)
- (Terminalvalue)(PjF, i, lO)](AjP, i, 10)
.
I
r= Alterp.ative2
:,.=' I: ~~ f1J1C"2,,.DIJit!~co~t-~~Ji~l£k.!W.J~Ic.P ~JPl =