464 CHAPTER 7 Counting and Combinatorics
Row 0 1
C(O, 0)
Row 1 1 1
C(1, 0) C(1, 1)
Row 2 1 2 1
C(2, 0) C(2, 1) C(2, 2)
Row 3 1 3 3 1
C(3, 0) C(3, 1) C(3, 2) C(3, 3)
Row 4 1 4 6 4 1
C(4, 0) C(4, 1) C(4, 2) C(4, 3) C(4, 4)
Column 0
D n 1 l Column
C(D, 1 0)
C(1, 0) C(1, 1) •un
Q21,0) Q2,1) Q(2, 2) Comn
C(1, 0) C(3, 1) C(3, 2) Q(1, 3)
cQA, 0) C(44, 1) C(6, 2) Q(4, 3)
Diagonal^0 1
Diagonal^3 1
Diagonal 2 1" ' 2 1
7(2, O) C(2 ,1) Q"..C2, 2)
Diagonal 3 1" -. 3". 3"-. l•x.
Diagonal 4 Q(4, 14 0) Q4, 1)• (42) 6 Q4, 4 3) Q4, 1 4)•
Figure 7.11 Rows, columns, and diagonals in Pascal's triangle.
Proof. The Row Sum is the content of Theorem 6 in Section 7.9.1. The proofs of the
other identities are left as exercises for the reader. M
By recognizing how to represent powers of integer variables as linear combinations of
binomial coefficients, the row, column, and diagonal sum identities can be used to evaluate
finite sums of such powers.
Theorem 9. (Sums of Powers) Let n > 1. Then,
(a) l+2+3+...+n=n(n+1)/2