Reverse Engineering for Beginners

(avery) #1

CHAPTER 21. STRUCTURES CHAPTER 21. STRUCTURES


_TEXT SEGMENT
_s$ = 8
_f PROC
mov eax, DWORD PTR _s$[esp+16]
movsx ecx, BYTE PTR _s$[esp+12]
mov edx, DWORD PTR _s$[esp+8]
push eax
mov eax, DWORD PTR _s$[esp+8]
push ecx
mov ecx, DWORD PTR _s$[esp+8]
push edx
movsx edx, BYTE PTR _s$[esp+8]
push eax
push ecx
push edx
push OFFSET $SG2802 ; 'a=%d; b=%d; c.a=%d; c.b=%d; d=%d; e=%d'
call _printf
add esp, 28
ret 0
_f ENDP


_s$ = -24
_main PROC
sub esp, 24
push ebx
push esi
push edi
mov ecx, 2
sub esp, 24
mov eax, esp
mov BYTE PTR _s$[esp+60], 1
mov ebx, DWORD PTR _s$[esp+60]
mov DWORD PTR [eax], ebx
mov DWORD PTR [eax+4], ecx
lea edx, DWORD PTR [ecx+98]
lea esi, DWORD PTR [ecx+99]
lea edi, DWORD PTR [ecx+2]
mov DWORD PTR [eax+8], edx
mov BYTE PTR _s$[esp+76], 3
mov ecx, DWORD PTR _s$[esp+76]
mov DWORD PTR [eax+12], esi
mov DWORD PTR [eax+16], ecx
mov DWORD PTR [eax+20], edi
call _f
add esp, 24
pop edi
pop esi
xor eax, eax
pop ebx
add esp, 24
ret 0
_main ENDP


One curious thing here is that by looking onto this assembly code, we do not even see that another structure was used inside
of it! Thus, we would say, nested structures are unfolded intolinearorone-dimensionalstructure.


Of course, if we replace thestruct inner_struct c;declaration withstruct inner_struct *c;(thus making
a pointer here) the situation will be quite different.

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