Audio Engineering

(Barry) #1
Measurement 61

Suppose we want to fi nd the natural logarithm of 2 (written ln 2). The base of natural
logarithms ise  2.7188281828. Then


log
log

.


.


.


2 0 30103


0 43425


0 69315


e







To verify this result,


e0 69315.  2.

T o fi nd log 2 of 26,


log
log

.


.


.


26


2


1 41497


0 30103


4 70044








The general case is


log
log

(^10) log
10
base
of the number
of the base
 of the number.. (2.38)


2.17 Semitone Intervals ...................................................................................................


Suppose that we need^122 (the semitone interval in music). We could write


log (^2) log
12


^122. (2.39)


Therefore


10 10
10
1 05946
2

2
12 03012
0 02508

12

log.
.
.










.


This is the same as multiplying 1.05946 by itself 12 times to obtain 2.


1 0 0.02508 is called the antilog of 0.02508. The antilog is also written as log ^1 , antilog 10,
or 10 exp. All these terms mean exactly the same thing.

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