FIGURE 2.2 (Continued)
31 D
D
VV
R 1
Atx 1 : when x 1 < L
Atx: when x < a Atx: when x < a
R
W
2
x
aaL
x 1
M (max) =
(a – x)
Wa
2
M
M =
W
2
At center:
At free ends:
D =
Wa^2 (3L + 2a)
12 EI
D =
Wa L^2
16 EI
R = R 1 = V (max) =
W
2
V =
W
2
CASE 12. Beam Overhanging Both Supports, Symmetrically Placed—Two Equal Concentrated Loads at Ends
W
2