36 MATHEMATICS
So, 2x^4 – 3x^3 – 3x^2 + 6x – 2 = (x^2 – 2)(2x^2 – 3x + 1 ).
Now, by splitting –3x, we factorise 2x^2 – 3x + 1 as (2x – 1)(x – 1). So, its zeroes
are given by x =
1
2
and x = 1. Therefore, the zeroes of the given polynomial are
2, 2,^1 ,and 1.
2