QUADRATIC EQUATIONS 81
Therefore, the solutions of the equations are
3
2
x and 1.
Let us verify our solutions.
Putting
3
2
x in 2x^2 – 5x + 3 = 0, we get
332
2–5 3 0
22
✁ ✂ ✁ ✂✄ ☎
✆✞ ✝✟ ✆✞ ✝✟ , which is
correct. Similarly, you can verify that x = 1 also satisfies the given equation.
In Example 7, we divided the equation 2x^2 – 5x + 3 = 0 throughout by 2 to get
x^2 –
53
22
x✠ = 0 to make the first term a perfect square and then completed the
square. Instead, we can multiply throughout by 2 to make the first term as 4x^2 = (2x)^2
and then complete the square.
This method is illustrated in the next example.
Example 8 : Find the roots of the equation 5x^2 – 6x – 2 = 0 by the method of completing
the square.
Solution : Multiplying the equation throughout by 5, we get
25 x^2 – 30x – 10 = 0
This is the same as
(5x)^2 – 2 × (5x) × 3 + 3^2 – 3^2 – 10 = 0
i.e., (5x – 3)^2 – 9 – 10 = 0
i.e., (5x – 3)^2 – 19 = 0
i.e., (5x – 3)^2 =19
i.e., 5 x – 3 = ✡ 19
i.e., 5 x = 31 ✡ 9
So, x =
319
5
☛
Therefore, the roots are
319
5
☞
and
319
5
✌
.
Verify that the roots are
319
5
☞ and^319
5