The Foundations of Chemistry

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H(aq)NO 3 (aq)Cu(s)88nCu^2 (aq)NO(g)H 2 O()

We see that copper is oxidized; it is the reducing agent. Nitrate ions are reduced; they are the
oxidizing agent.

HNO 3 Cu88nCu^2 NOH 2 O
 2
 3

We make the totalincrease and decrease in oxidation numbers equal.

Oxidation Numbers Change/Atom Equalizing Changes Gives
Cu 0 88nCu 2 23(2) 6
N 5 88nN 2 32(3) 6

Now we balance the redox partof the reaction.

H 2NO 3   3Cu 88n 3Cu^2   2NO H 2 O

There are 6 O on the left in NO 3 ions. A coefficient of 4 before H 2 O balances O and gives
8 H on the right. So we need 8 Hions on the left to balance the net ionic equation.

8H(aq)2NO 3 (aq)3Cu(s)88n3Cu^2 (aq)2NO(g)4H 2 O()

This solution contains excess HNO 3 , so NO 3 is the only anion present in significant concen-
tration. Therefore, we add six more NO 3 ions to each side to give the total ionic equation.

8[H(aq)NO 3 (aq)]3Cu(s)88n3[Cu^2 (aq)2NO 3 (aq)]2NO(g)4H 2 O()

Now we can write the balanced formula unit equation.

8HNO 3 (aq)3Cu(s)88n3Cu(NO 3 ) 2 (aq)2NO(g)4H 2 O()

You should now work Exercise 52.

EXAMPLE 11-20 Balancing Redox Equations (CON method)
Drano drain cleaner is solid sodium hydroxide that contains some aluminum chips. When
Drano is added to water, the NaOH dissolves rapidly with the evolution of a lot of heat. The
Al reduces H 2 O in the basic solution to produce [Al(OH) 4 ]ions and H 2 gas, which gives the
bubbling action. Write the balanced net ionic and formula unit equations for this reaction.
Plan
We are given formulas for reactants and products. Recall that NaOH is a strong soluble base
(OHand H 2 O can be added to either side as needed). We apply our five-step procedure.
Solution
We write the unbalanced net ionic equation and assign oxidation numbers.

OH(aq)Al(s)H 2 O()88n[Al(OH) 4 ](aq)H 2 (g)

Copper is cleaned by dipping it into
nitric acid.


422 CHAPTER 11: Reactions in Aqueous Solutions II: Calculations


 1  5  2 0  2  2  2  1  2

The Drano reaction.

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