EXAMPLE 13-3 Vapor Pressure Versus Temperature
The normal boiling point of ethanol, C 2 H 5 OH, is 78.3°C, and its molar heat of vaporiza-
tion is 39.3 kJ/mol (Appendix E). What would be the vapor pressure, in torr, of ethanol at
50.0°C?
Plan
The normal boiling point of a liquid is the temperature at which its vapor pressure is 760
torr, so we designate this as one of the conditions (subscript 1). We wish to find the vapor
pressure at another temperature (subscript 2), and we know the molar heat of vaporization.
We use the Clausius–Clapeyron equation to solve for P 2.
Solution
P 1 760 torr at T 1 78.3°C273.2351.5 K
P 2 _?_atT 2 50.0°C273.2323.2 K
Hvap39.3 kJ/mol or 3.93 104 J/mol
We solve for P 2.
ln
ln 1.18 so e1.180.307
P 2 0.307(760 torr) 233 torr (lower vapor pressure
at lower temperature)
You should now work Exercise 58.
P 2
760 torr
P 2
760 torr
1
323.2 K
1
351.5 K
3.93 104 J/mol
8.314 mo
J
l K
P 2
760 torr
502 CHAPTER 13: Liquids and Solids
(Enrichment, continued)
TABLE 13-6 General Effects of Intermolecular Attractions on Physical
Properties of Liquids
Volatile Liquids Nonvolatile Liquids
(weak intermolecular (strong intermolecular
Property attractions) attractions)
cohesive forces low high
viscosity low high
surface tension low high
specific heat low high
vapor pressure high low
rate of evaporation high low
boiling point low high
heat of vaporization low high