We can also write the thermochemical equation as
C 2 H 5 OH()3O 2 (g)88n2CO 2 (g)3H 2 O() H1367 kJ/mol rxn
The negative sign indicates that this is an exothermicreaction (i.e., it gives offheat).
We always interpret Has the enthalpy change for the reaction as written; that is,
as (enthalpy change)/(mole of reaction), where the denominator means βfor the
number of moles of each substance shown in the balanced equation.β
We can then use several unit factors to interpret this thermochemical equation.
The reverse reaction would require the absorption of 1367 kJ under the same conditions;
1367 kJ2CO 2 (g)3H 2 O()88nC 2 H 5 OH()3O 2 (g)
That is, it is endothermic,with H1367 kJ.
2CO 2 (g)3H 2 O()88nC 2 H 5 OH()3O 2 (g) H1367 kJ/mol rxn
It is important to remember the following conventions regarding thermochemical equa-
tions:
1.The coefficients in a balanced thermochemical equation refer to the numbers of
molesof reactants and products involved. In the thermodynamic interpretation
of equations we neverinterpret the coefficients as numbers of molecules.Thus, it
is acceptable to write coefficients as fractions rather than as integers, when neces-
sary.
2.The numerical value of H(or any other thermodynamic change) refers to the
number of molesof substances specified by the equation. This amount of change
of substances is called one mole of reaction,so we can express Hin units of
energy/mol rxn. For brevity, the units of Hare sometimes written kJ/mol or
even just kJ. No matter what units are used, be sure that you interpret the ther-
modynamic change per mole of reaction for the balanced chemical equation to which
it refers.If a different amount of material is involved in the reaction, then the
H(or other change) must be scaled accordingly.
3.The physical states of all species are important and must be specified. Heat is
given off or absorbed when phase changes occur, so different amounts of heat
could be involved in a reaction depending on the phases of reactants and prod-
ucts.
4.The value of Husually does not change significantly with moderate changes in
temperature.
1367 kJ given off
3 mol H 2 O() formed
1367 kJ given off
2 mol CO 2 (g) formed
1367 kJ given off
3 mol O 2 (g) consumed
1367 kJ given off
mol C 2 H 5 OH() consumed
1367 kJ given off
mol of reaction
15-5 Thermochemical Equations 599
C 2 H 5 OH()3O 2 (g)
H1367 kJ
2CO 2 (g)3H 2 O()
Before we know what a value of H
means, we must know the balanced
chemical equation to which it refers.
Increasing enthalpy
88888888888888888888888888n
8888888888888888888888n
See the Saunders Interactive
General Chemistry CD-ROM,
Screen 6.15, Enthalpy Changes for
Chemical Reactions.