4.17 102 M^1 486 M^1 486 M^1 417 M^1 903 M^1[NOBr]1.11 10 ^3 M (46.2% remains unreacted)Thus, 53.8% of the original concentration of NOBr reacts within the first 5 minutes. This is
reasonable because, as you can easily verify, the reaction has an initial half-life of 257 seconds,
or 4.29 minutes.
You should now work Exercises 35 and 38.
Zero-Order Reaction
For a reaction aA n products that is zero order, the reaction rate is independent of
concentrations. We can write the rate-law expression as
rate k
The corresponding integrated rate equation is
[A][A] 0 akt (zero order)and the half-life is
t1/2 (zero order)Table 16-2 summarizes the relationships that we have presented in Sections 16-3 and
16-4.
[A] 0
2 ak[A]
t1
a1
903 M^11
[NOBr]1
[NOBr]16-4 Concentration versus Time: The Integrated Rate Equation 669TABLE 16-2 Summary of Relationships for Various Orders of the Reaction
aAnProductsOrderZero First SecondRate-law expression ratek ratek[A] ratek[A]^2
Integrated rate equation [A][A] 0 akt ln
[
[A
A]
]0
akt or
[A1
]
[A1
] 0aktlog [
[A
A]
]^0
2.a
3k
0t
3Half-life, t1/2
[
2A
a]
k^0
ln
ak2
0.
a6
k93
ak[1
A] 0