The Foundations of Chemistry

(Marcin) #1
4.17 102 M^1  486 M^1

 486 M^1  417 M^1  903 M^1

[NOBr]1.11 10 ^3 M (46.2% remains unreacted)

Thus, 53.8% of the original concentration of NOBr reacts within the first 5 minutes. This is
reasonable because, as you can easily verify, the reaction has an initial half-life of 257 seconds,
or 4.29 minutes.


You should now work Exercises 35 and 38.


Zero-Order Reaction


For a reaction aA n products that is zero order, the reaction rate is independent of
concentrations. We can write the rate-law expression as


rate k


The corresponding integrated rate equation is


[A][A] 0 akt (zero order)

and the half-life is


t1/2 (zero order)

Table 16-2 summarizes the relationships that we have presented in Sections 16-3 and
16-4.


[A] 0

2 ak

[A]

t

1

a

1

903 M^1

1

[NOBr]

1

[NOBr]

16-4 Concentration versus Time: The Integrated Rate Equation 669

TABLE 16-2 Summary of Relationships for Various Orders of the Reaction
aAnProducts

Order

Zero First Second

Rate-law expression ratek ratek[A] ratek[A]^2


Integrated rate equation [A][A] 0 akt ln 


[
[

A
A

]
]

0
akt or 
[A

1
]


[A

1
] 0

akt

log 

[
[

A
A

]
]

^0 
2.

a
3

k
0

t
3




Half-life, t1/2 


[
2

A
a

]
k

^0


ln
ak

2


0.
a

6
k

93
 
ak[

1
A] 0



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