It is reasonable to assume that x(from the ionization of NH 3 ) is small, because NH 3 is a weak
base (rxn 2), and its ionization is further suppressed by the high concentration of NH 4 formed
by the soluble salt, NH 4 Cl (rxn 1).
Introducing these assumptions gives
0
0
.
.
1
2
0
0
x
1.8^10 ^5 M and x3.6^10 ^5 M
xM [OH]3.6 10 ^5 M so pOH4.44 and pH9.56
You should now work Exercise 10.
In Example 18-14 we calculated [OH] and pH for 0.20 Maqueous NH 3. Compare those
results with the values obtained in Example 19-3 (Table 19-2). The concentration of OH
is 53 times greaterin the solution containing only 0.20 Maqueous NH 3 than in the solu-
tion to which 0.10 mol/L NH 4 Cl has been added. This is another demonstration of the
common ion effect.
We can derive a relationship for [OH] in a solution containing a weak base, B, plus
a salt that contains the cation, BH, of the weak base, just as we did for weak acids. In
general terms the equation for the ionization of a monoprotic weak base and its Kbexpres-
sion are
BH 2 O 34 BHOH and Kb
Solving the Kbexpression for [OH] gives
[OH]Kb
Taking the logarithm of both sides of the equation gives
log [OH]log Kblog
Multiplication by 1 and rearrangement gives another form of the Henderson–Hasselbalch
equationfor solutions containing a weak base plus a salt of the weak base.
pOHpKblog where pKblog Kb (base/salt buffer)
[BH]
[B]
[B]
[BH]
[B]
[BH]
[BH][OH]
[B]
19-1 The Common Ion Effect and Buffer Solutions 799
TABLE 19-2 Comparison of [OH]and pH in Ammonia and Ammonium
Chloride—Ammonia Solutions
Solution % NH 3 Ionized [OH]pH
0.20 Maq NH 3 0.95% 1.9 10 ^3 M 11.28
0.20 Maq NH 3 pH1.72
and 0.018% 3.6 10 ^5 M 9.56
0.10 Maq NH 4 Cl
The percent ionization of NH 3 in this
solution is
100%0.018%.
3.6 10 ^5 Mionized
0.20Moriginal
B and BHrepresent the weak base
and its conjugate acid, respectively—
for example, NH 3 and NH 4 .
The two solutions in Table 19-2, in
the presence of universal indicator.
The NH 3 solution is on the left.
Can you calculate the percentage of
NH 3 that is ionized in these two
solutions?