Problems 103
Inf. line H1.2
+0.6Inf. line MK
(m)11.25–8.325 =2.925NP(MK) 11.1–9.0=2.1+
−
1.05yxyk= 11.25m11H H
A′ B′12m
RA RBFHAB
ACf=12mf 0 =2m
ak= 18m
l=48mk11.25
(yK-f 0 )⋅IL(H)
8.325 9.0 IL(MK^0 )11.1
+
Construction
Inf. line MK
(m)Fig. 4.17 Three-hinged arch with complex tie. Influence lines forHandMk
Problems.......................................................................
4.1.Design diagram of symmetrical three-hinged arch is presented in Fig.P4.1.
Construct the influence lines for internal forces at sectionnusing the nil point
method.
C
nP= 1Fig. P4.1
4.2.Design diagram of nonsymmetrical three-hinged arch is presented in Fig.P4.2.
Construct the following influence lines (a) for vertical reactions at arch supportsA
andB; (b) for thrust; and (c) for internal forces at sectionskandn. Use the nil point
method. Take into account indirect load application.