126 5Cables
HqNHWN
qC
W=q 0 sDFree body diagram
OxayBase of catenarys
Cds dy
ABdxDH W=q 0 sDesign diagram NFig. 5.8 Design diagram of the catenary. Free body diagram for portionCDand force triangle
The final results may be conveniently expressed in terms of additional parameter
aDH=q 0. This parameter is measured from the lowest pointCof the cable and
defines an originOand the lineO-xcalled a base of catenary (or chain line). In
terms ofaandsthe normal force, accordingly (5.21) becomes
NDq 0p
a^2 Cs^2 : (5.22)The relationship between coordinatesxandsin differential form is
dxDdscosDdsH
NDaq 0
q 0p
a^2 Cs^2dsDads
p
a^2 Cs^2:Integrating this equation from pointC.0; a/toD.x; y/allows us to calculate the
x-coordinate of any point of the cable in terms ofsandaDH=q 0
xDZs0ads
p
a^2 Cs^2Dasinh^1s
a: (5.23)The inverse relation, i.e., the solution of (5.23) with respect tosis
sDasinhx
a: (5.24)This formula allows us to obtain some useful relationships in terms of intensity load
q 0 and thrustH.
The length of the cable from lowest pointCtoD.x; y/is
LCDDH
q 0sinhq 0
Hx: (5.25)