126 5Cables
H
q
N
H
W
N
q
C
W=q 0 s
D
Free body diagram
O
x
a
y
Base of catenary
s
C
ds dy
A
B
dx
D
H W=q 0 s
Design diagram N
Fig. 5.8 Design diagram of the catenary. Free body diagram for portionCDand force triangle
The final results may be conveniently expressed in terms of additional parameter
aDH=q 0. This parameter is measured from the lowest pointCof the cable and
defines an originOand the lineO-xcalled a base of catenary (or chain line). In
terms ofaandsthe normal force, accordingly (5.21) becomes
NDq 0
p
a^2 Cs^2 : (5.22)
The relationship between coordinatesxandsin differential form is
dxDdscosDds
H
N
D
aq 0
q 0
p
a^2 Cs^2
dsD
ads
p
a^2 Cs^2
:
Integrating this equation from pointC.0; a/toD.x; y/allows us to calculate the
x-coordinate of any point of the cable in terms ofsandaDH=q 0
xD
Zs
0
ads
p
a^2 Cs^2
Dasinh^1
s
a
: (5.23)
The inverse relation, i.e., the solution of (5.23) with respect tosis
sDasinh
x
a
: (5.24)
This formula allows us to obtain some useful relationships in terms of intensity load
q 0 and thrustH.
The length of the cable from lowest pointCtoD.x; y/is
LCDD
H
q 0
sinh
q 0
H
x: (5.25)