542 14 Dynamics of Elastic Systems
The general solution of (14.18)is
X.x/DAcoshkxCBsinhkxCCcoskxCDsinkx; (14.19)
whereA, B, C,andDmay be calculated using theboundaryconditions.
The natural frequency!of a beam is defined by equation
!Dk^2
r
EI
m
D
^2
l^2
r
EI
m
; whereDkl: (14.20)
To obtain frequency equation using general solution (14.19), the following algo-
rithm is recommended:
Step 1.Represent the mode shape in the general form (14.19), which contains four
unknown constants.
Step 2.Determine constants using the boundary condition atxD 0 andxDl.
Thus, the system of four homogeneous algebraic equations is obtained.
Step 3.The nontrivial solution of this system represents a frequency equation.
Example 14.5.Calculate the frequencies of free vibration and find the correspond-
ing mode shapes for pinned-pinned beam. The beam has lengthl, mass per unit
lengthm, modulus of elasticityE, and moment of inertia of cross-sectional areaI.
Solution.The shape of vibration may be presented in form (14.19). For pinned-
pinned beam displacement and bending moment atxD 0 and atxDlequal zero.
Expression for bending moment is
X^00 .x/Dk^2 .AcoshkxCBsinhkxCcoskxDsinkx/ :
ConditionsX.0/D 0 andX^00 .0/D 0 leads to the equations
ACCD 0
ACD 0
ThusADCD 0.
ConditionsX.l/D 0 andX^00 .l /D 0 leads to the equations
BsinhklCDsinklD 0
BsinhklDsinklD 0
ThusBD 0 andDsinklD 0. Non-trivial solution occurs, if sinklD 0 .This
is frequency equation. Solution of this equation iskl D ; 2;:::Thus, the
frequencies of vibration are
!Dk^2
r
EI
m
;! 1 D
3:1416^2
l^2
r
EI
m
;! 2 D
6:2832^2
l^2
r
EI
m