68 3 Multispan Beams and Trusses
Example 3.2.The structure in Fig.3.23is subjected to a uniformly distributed load
qwithin the entire spanL:Calculate the internal forcesTandDin the indicated
elements.
Solution.The thrust of the arch chain equals
HDqHDq
1
2
L
2d
f
D
qLd
f
;
whereHis area of the influence line forHunder the loadq. After that, the required
forceTaccording to (3.2)is
TD
H
cos ̨ 1
D
qLd
fcos ̨ 1
:
We can see that in order to decrease the forceTwe must increase the heightf
and/or decrease the angle ̨ 1.
To calculate forceD, we can use section 2-2 and consider the equilibrium of the
right part of the structure:
D!
X
YD 0 W
DsinˇCRBCTsin ̨ 1 D^0 !DD
1
sinˇ
qL
2
qLd
f
tan ̨ 1
:
Thus, this problem is solved using the fixed and moving load approaches: thrustH
is determined using corresponding influence lines, while internal forcesDandT
are computed usingHand the classical method of through sections.
3.5.3 Complex Trusses.............................................
Complex trusses are generated using special methods to connect rigid discs. These
methods are different from those used to create the simple trusses, three-hinged
trusses, etc. analyzed in the previous sections of this chapter. An example of a com-
plex truss is a Wichert truss.
Figure3.24presents a design diagram of a typical Wichert truss. As before, stat-
ical determinacy of the structure can be verified by the formulaWD2JSS 0 ,
whereJ,S,andS 0 are the number of hinged joints, members, and constraints of
Fig. 3.24 Wichert truss
B
C 1
A
1 2