Problems 97referred to the motor shaft. When J 0 and are multiplied by 1/n^2 ,the inertia and
viscous-friction coefficient are expressed in terms of the output shaft. Introducing new parameters
defined bymoment of inertia referred to the output shaftviscous-friction coefficient referred to the output shaftthe transfer function G(s)given by Equation (3–51) can be simplified, yieldingorwhereThe block diagram of the system shown in Figure 3–29(b) can thus be simplified as shown in
Figure 3–29(c).Km=K
B
, Tm=
J
B
=
Ra J 0
Ra b 0 +K 2 K 3G(s)=Km
sATm s+ 1 BG(s)=K
Js^2 +BsK=K 0 K 1 K 2 nRaB =Cb 0 +AK 2 K 3 RaBDn^2 =J =J 0 n^2 =b 0 +AK 2 K 3 RaBProblems
B–3–1.Obtain the equivalent viscous-friction coefficient
beqof the system shown in Figure 3–30.
B–3–2.Obtain mathematical models of the mechanical sys-
tems shown in Figures 3–31(a) and (b).xb 3yb 2b 1 k m(a)No frictionx (Output)u(t)
(Input force)m(b)No frictionx (Output)u(t)
(Input force)k 1 k 2Figure 3–31
Mechanical systems.Figure 3–30
Damper system.