Modern Control Engineering

(Chris Devlin) #1

Section 6–2 / Root-Locus Plots 271


The characteristic equation for this closed-loop system is obtained by setting the


denominator of the right-hand side of Equation (6–1) equal to zero. That is,


or


(6–2)


Here we assume that G(s)H(s)is a ratio of polynomials in s.[It is noted that we


can extend the analysis to the case when G(s)H(s)involves the transport lag e–Ts.]


SinceG(s)H(s)is a complex quantity, Equation (6–2) can be split into two equations


by equating the angles and magnitudes of both sides, respectively, to obtain the


following:


Angle condition:


(6–3)


Magnitude condition:


(6–4)


The values of sthat fulfill both the angle and magnitude conditions are the roots of


the characteristic equation, or the closed-loop poles. A locus of the points in the


complex plane satisfying the angle condition alone is the root locus. The roots of


the characteristic equation (the closed-loop poles) corresponding to a given value


of the gain can be determined from the magnitude condition. The details of applying


the angle and magnitude conditions to obtain the closed-loop poles are presented


later in this section.


In many cases,G(s)H(s)involves a gain parameter K,and the characteristic equa-


tion may be written as


Then the root loci for the system are the loci of the closed-loop poles as the gain Kis


varied from zero to infinity.


Note that to begin sketching the root loci of a system by the root-locus method we


must know the location of the poles and zeros of G(s)H(s).Remember that the angles


of the complex quantities originating from the open-loop poles and open-loop zeros to


the test point sare measured in the counterclockwise direction. For example, if G(s)H(s)


is given by


G(s)H(s)=


KAs+z 1 B


As+p 1 BAs+p 2 BAs+p 3 BAs+p 4 B


1 +


KAs+z 1 BAs+z 2 BpAs+zmB


As+p 1 BAs+p 2 BpAs+pnB


= 0


∑G(s)H(s)∑= 1


/G(s)H(s)=; 180 °(2k+1) (k=0, 1, 2,p)


G(s)H(s)=- 1


1 +G(s)H(s)= 0

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