Once the attenuation factor ahas been determined on the basis of the required phase-lead
angle, the next step is to determine the corner frequencies v=1/Tandv=1/(aT)of the lead
compensator. Notice that the maximum phase-lead angle fmoccurs at the geometric mean of the
two corner frequencies, or
The amount of the modification in the magnitude curve at due to the inclusion
of the term (Ts+1)/(aTs+1)isNote thatWe need to find the frequency point where, when the lead compensator is added, the total mag-
nitude becomes 0 dB.
From Figure 7–145 we see that the frequency point where the magnitude of G 1 (jv)is
–6.7778dB occurs between v=1and 10 radsec. Hence, we plot a new Bode diagram of
G 1 (jv)in the frequency range between v=1and 10 to locate the exact point where
G 1 (jv)=–6.7778dB. MATLAB Program 7–25 produces the Bode diagram in this frequency
range, which is shown in Figure 7–146. From this diagram, we find the frequency point where
occurs at v=6.5686radsec. Let us select this frequency to be the new
gain crossover frequency, or vc=6.5686radsec. Noting that this frequency corresponds to
orwe obtainand1
aT=
vc
1 a=
6.5686
1 0.21
=14.3339
1
T
=vc 1 a=6.5686 1 0.21=3.0101vc=1
1 aT1 A 1 aTB,@G 1 (jv)@=-6.7778 dB1
1 a=
1
1 0.21
=6.7778 dB2
1 +jvT
1 +jvaT2
v= 11 aT= 4
1 +j1
1 a1 +ja1
1 a4 =
1
1 av= 1 A 1 aTBv= 1 A 1 aTB.550 Chapter 7 / Control Systems Analysis and Design by the Frequency-Response MethodMATLAB Program 7–25
num = [20];
den = [1 1 0];
w = logspace(0,1,100);
bode(num,den,w)
title('Bode Diagram of G1(s) = 20/[s(s + 1)]')
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