Modern Control Engineering

(Chris Devlin) #1
Section 10–8 / Quadratic Optimal Regulator Systems 793

frequency-response method. If the system designed has poor stability margins, it


is possible that the designed system may become unstable if the mathematical


model involves uncertainties.


7.Note that for nth-order systems, classical design methods (root-locus and


frequency-response methods) yield low-order compensators (first or second order).


Since the observer-based controllers are nth-orderCor(N-m)th-order if the


minimum-order observer is usedDfor an nth-order system, the designed system


will become 2nth order Cor(2n-m)th orderD. Since lower-order compensators are


cheaper than higher-order ones, the designer should first apply classical methods


and, if no suitable compensators can be determined, then try the pole-placement-


with-observer design approach presented in this chapter.


10–8 Quadratic Optimal Regulator Systems


An advantage of the quadratic optimal control method over the pole-placement method


is that the former provides a systematic way of computing the state feedback control gain


matrix.


Quadratic Optimal Regulator Problems. We shall now consider the optimal


regulator problem that, given the system equation


(10–112)


determines the matrix Kof the optimal control vector


(10–113)


so as to minimize the performance index


(10–114)


whereQis a positive-definite (or positive-semidefinite) Hermitian or real symmetric


matrix and Ris a positive-definite Hermitian or real symmetric matrix. Note that the


second term on the right-hand side of Equation (10–114) accounts for the expenditure


of the energy of the control signals. The matrices QandRdetermine the relative


importance of the error and the expenditure of this energy. In this problem, we assume


that the control vector u(t)is unconstrained.


As will be seen later, the linear control law given by Equation (10–113) is the optimal


control law. Therefore, if the unknown elements of the matrix Kare determined so as


to minimize the performance index, then u(t)=–Kx(t)is optimal for any initial state


x(0). The block diagram showing the optimal configuration is shown in Figure 10–35.


J=


3


q

0

(xQx+u Ru)dt


u(t)=-Kx(t)


x# =Ax+Bu


x.=Ax+ Bu

u x


  • K


Figure 10–35
Optimal regulator
system.

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