834 Chapter 10 / Control Systems Design in State SpaceTaking the conjugate transpose of both sides of Equation (10–146), we haveSinceKe=K*, this last equation is the same as Equation (10–159). Thus, we obtained Equation
(10–159) by considering the dual problem.
A–10–11. Consider an observed-state feedback control system with a minimum-order observer described
by the following equations:
(10–162)(10–163)
whereAxais the state variable that can be directly measured, and corresponds to the observed state
variables.B
Show that the closed-loop poles of the system comprise the closed-loop poles due to pole
placementCthe eigenvalues of matrix (A-BK)] and the closed-loop poles due to the minimum-
order observer [the eigenvalues of matrix
Solution.The error equation for the minimum-order observer may be derived as given by
Equation (10–94), rewritten thus:
(10–164)
whereFrom Equations (10–162) and (10–163), we obtain(10–165)
Combining Equations (10–164) and (10–165) and writingwe obtain(10–166)Equation (10–166) describes the dynamics of the observed-state feedback control system with a
minimum-order observer. The characteristic equation for this system isor
@s I-A+BK@@s I-Abb+Ke Aab@ = 02 s^ I-A+BK
0- BKb
s I-Abb+Ke Aab
(^2) = 0
B
x#
e
#R = B
A-BK
0
BKb
Abb-Ke AabRB
x
eR
K= CKaKbD=Ax-BKex- c
0
edf=(A-BK) x+BKc
0
ed
x# =Ax-BK x =Ax-BKc
xa
xb
d=Ax-BKcxa
xb-ed
e=xb-xbe# =AAbb-Ke AabB eAAbb-Ke AabBDxbx= c
xa
xbd, x= c
xa
xbd
u =-Kxy =Cxx# =Ax+BuK=AT-^1 BF
an-an
an- 1 - an- 1
a 1 - a 1V =(T*)-^1 F
an-an
an- 1 - an- 1
a 1 - a 1V =(WN*)-^1 F
an-an
an- 1 - an- 1
a 1 - a 1V
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