7 · OXIDATION AND REDUCTION
Oxidizing and reducing agents
Anoxidizing agentis a substance that takes up electrons during a chemical reaction
and, in doing so, becomes reduced. A reducing agentsupplies the electrons in this
process and so becomes oxidized.
7.3
104
Oxidizing and
reducing agents
Look back at the redox
ladder for sulfur in Exercise
7D:
(i) Which sulfur species
can act as both
reducing and oxidizing
agents in different
chemical reactions?
(ii)Which sulfur species
can only act as
oxidizing agents and
why?
(iii)Which sulfur species
can only act as
reducing agents and
why?
Exercise 7F
Example 7.1
When iron is heated in chlorine gas, iron(III) chloride is
produced. The ‘ordinary’ equation is:
2Fe(s)3Cl 2 (g)2FeCl 3 (s)
The redox half-equations are
Fe(s)Fe^3 (s)3e
Cl 2 (g)2e2Cl(s)
Here, iron is acting as a reducing agentbecause it supplies electrons to chlorine
and is oxidized.
Chlorine is acting as an oxidizing agentbecause it accepts electrons from iron and
isreduced.
Writing and balancing redox equations
In order to write a redox equation, it is first necessary to write the two half-reactions
that identify the oxidation and reduction processes taking place. The overall redox
equation is then obtained by adding these two half-reactions together, so that the
electrons in each half reaction cancel out.
To write the half reactions, follow these simple rules:
1.Identify the atoms that are oxidized and reduced, using the oxidation number
method.
Most of the reactions that you will come across at this stage, will occur in neutral or acid
solution, and step 2 applies.
2.Balance the half-reactions:
(i) Make sure that there are the same number of atoms of the element that is
oxidized (or reduced) on each side of the half-reaction.
(ii)If there are any oxygen atoms present, balance them by adding water molecules
to the other side of the half-reaction.
(iii)If there are hydrogen atoms present, balance them by adding hydrogen ions on
the other side of the half-reaction.
(iv)Make sure that the half-reactions have the same overall charge on each side by
adding electrons.
Note that the rules are slightly different if the reaction occurs in basic solution:
hydrogen atoms are balanced using H 2 O molecules and then the same number of
OHions are added to the opposite side of the equation to balance the oxygens.
Carry on as before, adding electrons to balance the charges.
7.4