142 9 · CALCULATING CONCENTRATIONS
Example 9.4 (continued)
Express this ratio as a fraction:
amount of HCl in moles 1
amount of KOH in moles
1
Since the amount of substance in moles volumemolar concentration, we can
substitute:
volmolar conc HCl 1
volmolar conc KOH
1
Substitute the values given in the equation:
25.0/1000molar concentration of HCl
1
37.5/10000.500 1
Therefore, the molar concentration of HCl is
37.50.500
0.750 mol dm^3
25
Calculation of unknown concentrations by titration
Use approximate atomic masses for these calculations.
(i) How much dilute sulfuric acid of concentration 1.0 mol dm^3 will react completely with
25 cm^3 of potassium hydroxide solution of concentration 4.0 mol dm^3?
H 2 SO 4 (aq) + 2KOH(aq) K 2 SO 4 (aq) + 2H 2 O(I)
(ii)A solution of sodium hydroxide contains 4.0 g dm^3. An endpoint is reached when 25 cm^3
of this solution react with 35 cm^3 of dilute nitric acid. Calculate the concentration of the
nitric acid.
NaOH(aq) + HNO 3 (aq)NaNO 3 (aq) + H 2 O(I)
(iii)A standard solution was prepared by dissolving 2.6061 g of anhydrous sodium carbonate
in deionized water and the solution diluted to 250 cm^3. A 25.0 cm^3 portion of this solution
was titrated against hydrochloric acid, using a suitable indicator. The endpoint was
reached after 18.7 cm^3 of acid had been added. Calculate the concentration of the
acid.
Na 2 CO 3 (aq) + 2HCl(aq) 2NaCl(aq) + H 2 O(I) + CO 2 (g)
(iv)How many cubic centimetres of a solution of hydrochloric acid, of concentration
2.0 mol dm^3 , are required to react completely with 50 cm^3 of a solution of Ba(OH) 2 that
contains 68.4 g dm^3?
2HCl(aq) + Ba(OH) 2 (aq)BaCl 2 (aq) + 2H 2 O(I)
Exercise 9E
Redox titrations
The technique of titration may also be used to determine the concentration of an
unknown solution, when the solutions react together in a redoxreaction. Potassium
permanganate (or potassium manganate(VII), KMnO 4 ) is a powerful oxidizing
agent and is used to estimate the concentration of many reducing agents. Potassium
permanganate solution is purple in colour, but is virtually colourless when reduced
to Mn^2 – it can therefore act as a self-indicator. As it is added to the reducing
solution it turns colourless, but at the endpoint a very small amount of excess