Handbook of Civil Engineering Calculations

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Calculation Procedure:


  1. Record the basic values of the previous calculation procedure
    The beam-column factors were devised in an effort to reduce the labor entailed in analyz-
    ing a given member as a beam column whenfa/Fa > 0.15. They are defined by B = AIS per
    inch (decimeter); a = 0.149 x 106 /in^4 (6201.9/dm^4 ).
    Let P denote the applied axial load and -Pauow the axial load that would be permitted in
    the absence of bending. The equations given in the previous procedure may be trans-
    formed to P + BMCm(Fa/Fb)a/[a - P(KL)^2 ] < Pallow, and PFJQ.6fy) + BMFJFb < Pallow,
    where KL, B 9 and a are evaluated with respect to the plane of bending.
    The basic values of the previous procedure are P = 160 kips (711.7 kN); M= 31.5
    ft-kips (42.71 kN-m); Fb = 22 kips/in^2 (151.7 MPa); Cm = 0.793.

  2. Obtain the properties of the section
    From the Manual for a W12 x 53, A = 15.59 in^2 (100.587 cm^2 ); Bx = 0.221 per inch (8.70
    per meter); ax = 63.5 x 10
    6
    in
    4
    (264.31 x 1Q
    3
    dm
    4
    ). Then when KL = 20 ft (6.1 m),Pallow =
    209 kips (929.6 kN).

  3. Substitute in the first transformed equation
    Thus, F 0 = Pallow/A = 209/15.59 = 13.41 kips/in^2 (92.461 MPa), P(KL)^2 = 160(24O)^2 =
    9.22 x 106 kip-in^2 (2.648 x 104 kN-m^2 ), and aj[ax - P(KL)^2 ] = 63.57(63.5 - 9.22) =1.17;
    then 160 + 0.221(31.5)(12)(0.793)(13.41/22)(1.17) = 207 < 209 kips (929.6 kN). This is
    acceptable.

  4. Substitute in the second transformed equation
    Thus, 160(13.41/22) + 0.221(31.5)(12)(13.41/22) = 148 < 209 kips (929.6 kN). This is
    acceptable. The Wl2 x 53 section is therefore satisfactory.


NET SECTION OF A TENSION MEMBER

The 7 x % in (177.8 x 6.35 mm) plate in Fig. 17 carries a tensile force of 18,000 Ib
(80,064.0 N) and is connected to its support with three^3 /4-in (19.05-mm) rivets in the
manner shown. Compute the maximum tensile stress in the member.


Calculation Procedure:


  1. Compute the net width
    of the member at each section
    of potential rupture
    The AISC Specification prescribes the man-
    ner of calculating the net section of a tension
    member. The effective diameter of the holes
    is considered to be Vs in (3.18 mm) greater
    than that of the rivets.
    After computing the net width of each
    section, select the minimum value as the ef-
    fective width. The Specification imposes an
    upper limit of 85 percent of the gross width.
    Refer to Fig. 17. From B to D 9 s = 1.25 in
    FIGURE 17 (31.750 mm), g = 2.5 in (63.50 mm); from D

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