Calculation Procedure:- Record the relevant properties of the W18 x 6O
The connection is shown in Fig. 5a. Referring to the row of rivets in Fig. Sb 9 consider that
there are n rivets having a uniform spacing/?. The moment of inertia and section modulus
of this rivet group with respect to its horizontal centroidal axis are
/.^..^i s-e^l p,Record the properties of the W18 x 60: d = 18.25 in (463.6 mm); b = 7.558 in (192
mm); &= 1.18 in (30.0 mm); tf = 0.695 in (17.7 mm); tw = 0.416 in (10.6 mm).
- Establish the capacity of a rivet
Thus: single shear, 9.02 kips (40.1 kN); double shear, 18.04 kips (80.2 kN); bearing on
beam web, 0.875(0.416)(48.5) = 17.65 kips (78.5 kN). - Determine the number of rivets required on line 1 as governed
by the rivet capacity
Try 15 rivets having the indicated disposition. Apply Eq. 3 with n = 11; then make the
necessary correction. Thus, /= 9(17)(17
2- 1)/12 - 2(9)
2
= 3510 in
2
(22,645 cm
2
)- S =
3510/24 = 146.3 in (3716 mm).
Let F denote the force on a rivet, and let the subscripts x and y denote the horizontal
- 1)/12 - 2(9)
FIGURE 5. Riveted moment connection.