Daily Rate: (27,531 lb/wk)/(5 d/wk) = 5506 Ib/d (2499.7 kg/d)
Hourly Rate: (5506 lb/d)/(6 h/d) = 918 Ib/h (416.8 kg/h)
- Size the belt thickener
Using the hourly rate of sludge calculated above, and a loading rate of 1,000 Ib/h per me-
ter of belt width, the size of the belt thickener is:
Belt Width =
918
I^ = 0.918 m (3.01 ft)
1000 Ib/h-m
v
'
Use one belt thickener with a 1.0 m belt width. Note that one identical belt thickener
should be provided as a spare.
The thickened sludge flow rate (S) in gal/day (m
3
/d) and the filtrate flow rate (F) in
gal/day (m
3
/d) are computed by developing solids balance and flow balance equations:
(a) Solids balance equation. Solids in = solids out, which implies that: solids in sludge
feed = solids in thickened sludge + solids in filtrate. Assume the following:
- Sludge feed specific gravity (s.g.) =1.01
- Thickened sludge s.g. = 1.03
- Filtrate s.g. = 1.0
- Suspended solids in filtrate = 900 mg/L = 0.09%
Therefore, the solids balance equation on a daily basis becomes:
5506 Ib = (S 9 gal/day)(8.34 lb/gal)(1.03)(0.05)
+ (F, gal/day)(8.34 lb/gal)(l .O)(0.0009) (1)
5506 Ib/d - 0.4295(5) + 0.0075(F)
(b) Flow balance equation. Flow in = flow out, which implies that: influent sludge
flow rate + washwater flow rate = thickened sludge flow rate + filtrate flow rate. Daily in-
fluent sludge flow rate = (58,000 gal/day)(7/5) - 81,200 gal/day (307.3 m^3 /d).
- Compute the thickened sludge and filtrate flow rates
Washwater flow rate is assumed to be 16 gal/min (1.0 L/s). Washwater flow rate varies
from 12 gal/min (0.757 L/s) to 30 gal/min (1.89 L/s) depending on belt thickener size.
Therefore, with an operating schedule of 6 h/d (360 min/d) the flow balance equation on a
daily basis becomes:
81,200 gal/day + (16 gal/min)(360 min/d) - S + F
86,960 gal/day = S + F (2)
Putting (Eq. 1) and (Eq. 2) in matrix format, and solving for thickened sludge flow rate
(S) and filtrate flow rate (F):
[" 0.4295 0.0075 ][" S] f 5506]
L 1 1 J [Fj [86,960J
S = 11,502 gal/day (43.5 m
3
/d) of thickened sludge at 5.0% solids
F= 75,458 gal/day (285.6 m
3
/d) of filtrate