294 9 Two point boundary value problems
point as the midpoint of the integration interval and compute safely the solution. This is the
topic of the next section.
9.4 Green’s function approach
A slightly different approach, which however still keeps the matching procedure discussed
above, is based on the computation of the Green’s function and its relation to the solution of
a differential equation with boundary values.
Consider the differential equation
−u(x)′′=f(x), x∈( 0 , 1 ), u( 0 ) =u( 1 ) = 0 , (9.23)
and using the fundamental theorem of calculus, there is a constantc 1 such that
u(x) =c 1 +
∫x
0
u′(y)dy,
and a constantc 2
u′(y) =c 2 +
∫y
0
u′′(z)dz.
This is true for any twice continuously differentiable functionu
Ifusatisfies the above differential equation we have then
u′(y) =c 2 −
∫y
0
f(z)dz.
which inserted into the equation forugives
u(x) =c 1 +c 2 x−
∫x
0
(∫y
0
f(z)dz
)
dy,
and defining
F(y) =
∫y
0
f(z)dz,
and performing an integration by parts we obtain
∫x
0
F(y)dy=
∫x
0
(∫y
0
f(z)dz
)
dy=
∫x
0
(x−y)f(y)dy.
This gives us
u(x) =c 1 +c 2 x−
∫x
0
(x−y)f(y)dy.
The boundary conditionu( 0 ) = 0 yieldsc 1 = 0 andu( 1 ) = 0 , resulting in
c 2 =
∫ 1
0
( 1 −y)f(y)dy,
meaning that we can write the solution as
u(x) =x
∫ 1
0
( 1 −y)f(y)dy−
∫x
0
(x−y)f(y)dy
The solution to our differential equation can be represented in a compact way using the
so-called Green’s functions, which are also solutions to our differential equation withf(x) = 0.