298 9 Two point boundary value problems
Compare these results with those obtained by solving the above differential equation as a
set of linear equations, as done in chapter 6. Which method would you prefer?
9.2.We are going to study the solution of the Schrödinger equation for a system with a
neutron and a proton (the deuteron) for a simple box potential. This potential will later be
replaced with a realistic one fitted to experimental phase shifts.
We begin our discussion of the Schrödinger equation with theneutron-proton (deuteron)
system with a box potentialV(r). We define the radial part of the wave functionR(r)and
introduce the definitionu(r) =rR(R)The radial part of the SE for two particles in their center-
of-mass system and with orbital momentuml= 0 is then
−
h ̄^2
2 m
d^2 u(r)
dr^2
+V(r)u(r) =E u(r), (9.26)
with
m= 2
mpmn
mp+mn
, (9.27)
wherempandmnare the masses of the proton and neutron, respectively. We use herem= 938
MeV. Our potential is defined as
V(r) =
0 r>a
−V 00 <r≤a
∞ r≤ 0
, (9.28)
displayed in Fig 9.1.
✲ x
0 a
−V 0
V(x)
Fig. 9.1Example of a finite box potential with value−V 0 in 0 <x≤a, infinitely large forx≤ 0 and zero else.
Bound states correspond to negative energyEand scattering states are given by positive
energies. The SE takes the form (without specifying the signofE)