c07 JWBS043-Rogers September 13, 2010 11:25 Printer Name: Yet to Come
94 EQUILIBRIUMandGB=G◦B+RTlnpB
1. 0where the 1.0 in the denominators signify that the partial pressures are relative to
the standard state of 1.0 bar. The difference between the chemical potentials of the
reactant state and product state isrG=∑
G(prod)−∑
G(react)which in this simple case isrG=GB−GA=G◦B−G◦A+RTlnpB
1. 0−RTlnpA
1. 0orrG=G◦+RTlnpB
pAAs the reaction progresses,rGis not zero andGof the reacting system is not constant
with timet,(∂G/∂t)T,p=0. When the chemical reaction has come to completion,
the pressure quotientQ=pB/pAhas arrived at a value such that(∂G/∂t)T,p=0,
hencerG=G◦+RTlnpB
pA= 0
The free energy change of the system has arrived at a Gibbs potential energy mini-
mum. Under these andonly under these conditions,wehaverG=0, so thatG◦=−RTlnpB
pA=−RTlnKeqThe expression is frequently written in the equivalent form:Keq=e−G
◦/RT7.2 GENERAL FORMULATION
A more general formulation of the equilibrium expressions above is given by the
reactionaA+bB+... = cC+dD+...