c03 JWBS043-Rogers September 13, 2010 11:24 Printer Name: Yet to Come
THERMODYNAMIC CYCLES 37
so the condition
∂
∂x
N(x,y)=
∂
∂y
M(x,y)
is a test for exactness.
3.2 THERMODYNAMIC CYCLES
The problem of inexact and exact differentials can be expressed in several ways.
Taking work as an example, workwisnot a thermodynamic function. The differential
of the workdwisnot exact. The work done in a thermodynamic process depends
upon the path. The integral
w=
∫V 2
V 1
f(T)pdv
is aline integral. The line integral cannot be evaluated until we know f(T), an
arbitrary function of the temperature. There is an infinite number of paths (ways of
getting fromV 1 toV 2 ), hence an infinite number of solutions to the work integral.
Consider two ways of taking a gas from thermodynamic state A with molar volume
V 1 to state B with molar volumeV 2. Let the substance be in the gaseous state. Let the
first path be an isothermal compression from 1.00 bar to 10.0 bars at 290 K followed
by anisobaric(constant pressure) temperature rise from 290 K to 310 K. The second
path will start with the isobaric temperature rise from 290 K to 310 K, followed by
an isothermal compression from 1.00 bar to 10.0 bars at 310 K. The beginning and
end points of the process are the same for both paths. For simplicity, assume that the
gas is nitrogen, which is nearly ideal over this temperature and pressure range. The
two paths are shown in Fig. 3.1.
The volumeV=RT/pcan be calculated after each step. The results are shown
at each corner of the rectangular diagram below. The volumes at each corner of the
diagram are larger on the left (before compression) than on the right and larger at the
top (after heating) than on the bottom.
2441 244.1
2660 266.0
A
B