x 10
1 x 1
01 x¼ 0 (4.80)
(compare this with the Fock matrix for the propenyl system). Solving this equation
(seeSection 4.3.3):
x 10
1 x 1
01 x¼xx 1
1 x" 1
11
0 xþ 11 x
01¼xðx^2 " 1 Þ"ðx" 0 Þþ 0 ¼x^3 "x"x¼x^3 " 2 x¼0 (4.81)This cubic can be factored (but in general polynomial equations require numeri-
cal approximation methods):
xðx^2 " 2 Þ¼0 so x¼0 and x^2 " 2 ¼0 or x¼,p
2From (a"E)/b¼x,E¼a"xbandx¼0 leads toE¼a
x¼þp
2 leads toE¼a"p
2 b
x¼"p
2 leads toE¼aþp
2 bSo we get the same energy levels as from matrix diagonalization (pffi
2 ¼1.414).
To find the coefficients we substitute the energy levels into the secular equations;
for the propenyl system these are, projecting from the secular equations for a
two-orbital system, Eqs.4.49:
ðH 11 "ES 11 Þc 1 þðH 12 "ES 12 Þc 2 þðH 13 "ES 13 Þc 3 ¼ 0
ðH 21 "ES 21 Þc 1 þðH 22 "ES 22 Þc 2 þðH 23 "ES 23 Þc 3 ¼ 0
ðH 31 "ES 31 Þc 1 þðHS 32 "ES 32 Þc 2 þðH 33 "ES 33 Þc 3 ¼ 0(4.82)
These can be simplified (Eqs.4.57, 4.61) toða"EÞc 1 þbc 2 þ 0 c 3 ¼ 0
bc 1 þða"EÞc 2 þbc 3 ¼ 0
0 c 1 þbc 2 þða"EÞc 3 ¼ 0(4.83)
For the energy levelE¼aþp
2 b(MO level 1,c 1 ), substituting into the first
secular equation we get
150 4 Introduction to Quantum Mechanics in Computational Chemistry