1.1 What is Chemistry?

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http://www.ck12.org Chapter 14. The Properties of Gases


T 1 = 25 ◦C+ 273 =298 K


T 2 = 50 ◦C+ 273 =323 K


V 1 =752 mL
V 2 =?
V 1
T 1

=


V 2


T 2


V 2 =


V 1 T 2


T 1


V 2 =


(752 mL)(323 K)
298 K
V 2 =815 mL

Gay-Lussac’s Law


Gay-Lussac’s Lawdescribes the relationship between pressure and absolute temperature:
P
T=k
P 1
T 1 =


P 2
T 2

Gay-Lussac’s law says that at a constant volume, the pressure of a gas is directly proportional to its absolute
temperature. This relationship is also sometimes attributed to Guillaume Amontons (1663–1705). Although his
work predated that of Gay-Lussac by over a century, the data on which he based his ideas were considerably less
precise, due to the cruder instrumentation available at the time.


Example 14.5


The gas in an aerosol can exerts a pressure of 3.00 atm at 25°C. Directions on the can warn the user not to keep the
can in a place where the temperature exceeds 52°C. What would the gas pressure in the can be at 52°C? Before you
begin, do you think the pressure should go up, down or stay the same?


Answer:


Again, don’t forget that all temperatures must be converted to absolute temperature (Kelvin).


T 1 = 25 ◦C+ 273 =298 K


T 2 = 52 ◦C+ 273 =325 K


P 1 = 3 .00 atm
P 2 =?
P 1
T 1

=


P 2


T 2


P 2 =


P 1 T 2


T 1


P 2 =


( 3 .00 atm)(325 K)
298 K
P 2 = 3 .27 atm

Note that the pressure increases, which would be expected if the temperature were to go up.

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