39.3 Dudeney’s Canterbury puzzle 3 1013
39.3 Dudeney’s Canterbury puzzle 3
7 × 2 8 = 1 9 6 = 3 4 × 5.
While 7 ×28 = 196, it is not true that 34 ×5 = 196. Move as few
counters as possible to make the equations valid.^2
2.^4 × 78 = 156 = 39×^2 to (27)(495)