Applied Statistics and Probability for Engineers

(Chris Devlin) #1
13-8

0.01 1.5 2 2.5 3 3.5 (for

0.02

0.03

0.04

0.05

0.06

0.07

0.08

0.10

0.20

0.30

0.40

0.50

0.60

0.70

0.80

φ α= 0.05)
2345

1.00

Probability of accepting the hypothesis

φ(forα= 0.01)

ν 1 = 1

α α

9
10
12



0.01 1 2 3 (for

0.02

0.03

0.04

0.05

0.06

0.07

0.08

0.10

0.20

0.30

0.40

0.50

0.60

0.70

0.80

φ α= 0.05)
1345

1.00

Probability of accepting the hypothesis

φ(forα= 0.01)

ν 1 = 2

2

ν 2 = 6

60
20
15

7

ν 1 = numerator degrees of freedom. ν 2 = denominator degrees of freedom.

= 0.05 = 0.01

ν = 6
7
8
9
10
12
15
20
30
60

6 = ν 2

15
20
30
60

7
8

30

12
10
9
8


α = 0.05

α = 0.01

2

Source: These curves are adapted with permission from Biometrika Tables for Statisticians,Vol.
2, by E. S. Pearson and H. O. Hartley, Cambridge University Press, Cambridge, 1972.

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