Applied Statistics and Probability for Engineers

(Chris Devlin) #1
13-10

0.01 1 2 3 (for

0.02

0.03

0.04

0.05

0.06

0.07

0.08

0.10

0.20

0.30

0.40

0.50

0.60

φ α= 0.05)
134

1.00

Probability of accepting the hypothesis

φ(forα= 0.01)

ν 1 = 7

2

0.01 1 2 3 (for

0.02

0.03

0.04

0.05

0.06

0.07

0.08

0.10

0.20

0.30

0.40

0.50

0.60

φ α= 0.05)
134

1.00

Probability of accepting the hypothesis

φ(forα= 0.01)

ν 1 = 8

2

0.70

0.80

0.70

0.80

15

8
7


ν 2

60

7
= 6

α = 0.05

α = 0.01

ν 2

60
30
20
12
10
9

= 6

α = 0.05
α = 0.01

30
20
15
12
10
9
8


PQ220 6234F.Ch 13_CD 5/8/02 7:54 PM Page 10 RK UL 6 RK UL 6:Desktop Folder:TEMP WORK:PQ220 MONT 8/5/2002:Ch 13:

Free download pdf