Applied Statistics and Probability for Engineers

(Chris Devlin) #1
13-13

2

.02

.03

.04

.05

.06

.07
.08

.10

Probability of accepting the hypothesis

.01

.20

.30

.40

.50

.60

.70
.80

1 345678
1234567 89101112

λ(forα= 0.05)
λ(forα= 0.01)

ν 1 = 4

2

.02

.03

.04

.05

.06

.07

.08

.10

Probability of accepting the hypothesis

.01

.20

.30

.40

.50

.60

.70
.80

1.00

1 345678 91011
1 2 3 4 5 6 7 8 9 10 11 12 13

λ(forα= 0.05)
λ(forα= 0.01)

ν 1 = 3

1.00

7
8

30

ν

7

15
30

8

α= .05
α= .01

9
10
12
20
60

6 =ν 2

10
12
15
20
60

2


9

= 6

α= .05
α= .01

PQ220 6234F.Ch 13_CD 5/8/02 7:54 PM Page 13 RK UL 6 RK UL 6:Desktop Folder:TEMP WORK:PQ220 MONT 8/5/2002:Ch 13:

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