factorial points, and let be the average of the nCrun at the center point. If the difference
is small, the center points lie on or near the plane passing through the factorial points,
and there is no curvature. On the other hand, if is large, curvature is present. A single-
degree-of-freedom sum of squares for curvature is given by(S14-12)where, in general, nFis the number of factorial design points. This quantity may be compared
to the error mean square to test for curvature. Notice that when Equation S14-12 is divided by
, the result is similar to the square of the tstatistic used to compare two means.
More specifically, when points are added to the center of the 2kdesign, the model we may
entertain iswhere the jjare pure quadratic effects. The test for curvature actually tests the hypothesesFurthermore, if the factorial points in the design are unreplicated, we may use the nCcenter
points to construct an estimate of error with nC 1 degrees of freedom.EXAMPLE S14-2 A chemical engineer is studying the percentage of conversion or yield of a process. There are
two variables of interest, reaction time and reaction temperature. Because she is uncertain about
the assumption of linearity over the region of exploration, the engineer decides to conduct a 2^2H 1 : akj 1jj^0H 0 : akj 1jj^0Y 0 akj 1jxjb
ijijxixjakj 1jjx^2 jˆ^2 MSE
°yF yCB1
nF1
nC¢2SSCurvaturenFnC 1 yF yC 22
nFnCyF yCyF yCyC14-10- 1+1 0
35
A = Reaction time (min)30 400- 1
115515016039.3 40.940.3
40.5
40.7
40.2
40.640.0 41.5B = Temperature (°C)Figure S14-4 The 2^2
design with five center
points for Example
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