13.1 Work, Mechanical Energy, Thermal Energy 375
the gravitational pull of the earth on the object (see Figure 13.2). The change in the potential
energy of the object when its elevation is changed is given by
(13.4)
where
mmass of the object (kg)
gacceleration due to gravity (9.81 m/s
2
)
¢hchange in the elevation ( m)
The SI unit for potential energy is also joule, a derived unit, and is obtained by substitut-
ing kg for the units of mass, and m/s
2
for the units of acceleration due to gravity, and m for the
elevation change:
In the British Gravitational U.S. Customary systems, the unit of potential energy is expressed
in lbf ft. As in the case with kinetic energy, keep in mind that it is the change in the poten-
tial energy that is of significance in engineering calculations. For example, the energy required
to lift an elevator from the first floor to the second floor is the same as lifting the elevator from
the third floor to the fourth floor, provided that the distance between each floor is the same.
Example 13.2 Calculate the energy required to lift an elevator and its occupant with a mass of 2000 kg for the
following situations: (a) between the first and the second floor,
(b) between the third and the fourth floor, (c) between the first
and the fourth floor. (See Figure 13.3.) The vertical distance
between each floor is 4.5 m.
We can use Equation (13.4) to analyze this problem; the
energy required to lift the elevator is equal to the change in its
potential energy, starting with
(a) change in potential energy mg¢h
(b) change in potential energy mg¢h
(c) change in potential energy mg¢h
1 2000 kg2a9.81
m
s
2 b113.5 m^2 264,870 J
1 2000 kg2a9.81
m
s
2 b14.5 m^2 88,290 J
1 2000 kg2a9.81
m
s
2 b14.5 m^2 88,290 J
potential energymgh 1 kg2a
m
s
2 b1m^2 N
#mJ
d
N
change in potential energy¢PEmg ¢h
h
m
m
■Figure 13.2
Change in potential energy of
an object.
m
h = 4.5 m
m
h = 4.5 m
m
h = 4.5 m
m
1
2
3
4
■Figure 13.3
A schematic diagram for
Example 13.2.
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