500 Chapter 15 MATLAB

Using MATLAB, create a table that shows the air

speed for the range of dynamic pressure of 500 Pa to

800 Pa. Use increments of 50 Pa.

15.15. Use MATLAB to solve Example 7.1. Recall that we ap-

plied the trapezoidal rule to determine the area of the

shape given. Create an Excel file with the given data,

and then import the file into MATLAB.

15.16. We will discuss engineering economics in Chapter 20.

Using MATLAB, create a table that can be used to look

up monthly payments on a car loan for a period of five

years. The monthly payments are calculated from

where

Amonthly payments in dollars

Ploan in dollars

iinterest rate; e.g., 7, 7.5, ..., 9

15.17. A person by the name ofSutterlandhas developed a

correlation that can be used to evaluate the viscosity of

air as a function of temperature. It is given by

where

mviscosity (N/s m

2

)

Ttemperature (K)

c 1 1.458  10

 6

c 2 110.4 K

Create a table that shows the viscosity of air as a

function of temperature in the range of 0°C (273.15 K)

to 100°C (373.15 K) in increments of 5°C. Also, cre-

ate a graph showing the value of viscosity as a function

of temperature.

15.18. In Chapter 11, we explained the concept of windchill

factors. The windchill values are determined empiri-

cally, and the common equivalent windchill tempera-

tureTequivalent(°C) is given by

Create a table that shows the windchill temperatures

for the range of ambient air temperature of  30 C 

Ta  10 C and wind speeds of 5 m/s 

V20 m/s.

15.19. Given the matrices:

, and

, perform the following operations

using MATLAB.

a.

b.

c.

d.

e.

15.20.Given the following matrices:

, and

calculate the determinant of [A] and [B] using

MATLAB. Which matrix is singular?

15.21.Solve the following set of equations using

MATLAB.

3 B 4 £

210 0

420 0

12  418

3 A 4 £ §,

210 0

16 6 14

12  418

§

3 A 45 C 6 ?

3 A 43 B 4 ?

33 A 4 ?

3 A 4  3 B 4 ?

3 A 4  3 B 4 ?

5 C 6 •

1

 2

4

¶

3 B 4 £

12  1

53 3

45  7

3 A 4 £ §

421

70  7

1  53

§,

1 Ta 332  33

Tequivalent0.045 1 5.27V

0.5

10.450.28V 2

a

kg

m#s#K

1/2

b

m

c 1 T

0.5

1 

c 2

T

AP≥

a

i

1200

ba 1 

i

1200

b

60

a 1 

i

1200

b

60

 1

¥

Interest Rate

Loan 7 7.5 8 8.5 9

10,000

15,000

20,000

25,000

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